an ap consists of 60terms if the first and the last term be 7 and125 respectively find 32nd term
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a=7 l=125 total terms = 60
last term is given by
a+(n-1)d= 125
7+(59)d=125
59d=118
d= 2
so now 32nd term
a+(n-1)d
7+(31)2
7+62
= 69
last term is given by
a+(n-1)d= 125
7+(59)d=125
59d=118
d= 2
so now 32nd term
a+(n-1)d
7+(31)2
7+62
= 69
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