an ap has 7 terms then the 6th term is 9 more than 3 Rd term and the product of first and last term is 40 find AP
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Step-by-step explanation:
ATQ, a6 = a3 + 9
a + 5d = a + 2d + 9
3d = 9
d = 3
Also, a1×a7 = 40
a × a+6d = 40
a²+6ad = 40 (putting value of d = 3)
a²+6a(3) = 40
a²+18a = 40
a²+18a-40 = 0
a²+20a-2a-40=0
a(a+20)-2(a+20) = 0
(a+20) = 0 and (a-2) = 0
a = -20 and a = 2
If a = -20
-20, -17, -14....
If a = 2
2, 5, 8, 11....
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