An ap has a common difference equal to 10 and its 6th term is 52. Find its 16th term
Answers
Answered by
4
Hii ☺ !!
Here is your answer ✓ ✓ ✓ ✓
Common difference ( D ) = 10
Let first term = a
And,
6th term = 52
First term + 5( Common difference) = 52
a + 5d = 52
a + 5 × 10 = 52
a + 50 = 52
a = 52 - 50
a = 2
First term ( a ) = 2.
therefore,
16th term = a + 15d = 2 + 15 × 10
16th term = 2 + 150
16th term = 152.
☺ Hope it will help you ☺
BySaniyaAnwar
#BeBrainly
Here is your answer ✓ ✓ ✓ ✓
Common difference ( D ) = 10
Let first term = a
And,
6th term = 52
First term + 5( Common difference) = 52
a + 5d = 52
a + 5 × 10 = 52
a + 50 = 52
a = 52 - 50
a = 2
First term ( a ) = 2.
therefore,
16th term = a + 15d = 2 + 15 × 10
16th term = 2 + 150
16th term = 152.
☺ Hope it will help you ☺
BySaniyaAnwar
#BeBrainly
Answered by
5
Hii Mate !!
Here is your answer :
Solution :
Common difference = 10
And , 6th term = 52
a + 5d = 52
a + 5*10 = 52
a + 50 = 52
a = 52 - 50
a = 2
First term of the given AP = 2
And , Common difference = 10.
Therefore,
16th term. ( T16 ) = a + 15d
16th term = 2 + 15*10
16th term = 2 + 150
16th term = 152.
☺ Hope it helps you ♥
By Rishi403
BeBrainly.
Here is your answer :
Solution :
Common difference = 10
And , 6th term = 52
a + 5d = 52
a + 5*10 = 52
a + 50 = 52
a = 52 - 50
a = 2
First term of the given AP = 2
And , Common difference = 10.
Therefore,
16th term. ( T16 ) = a + 15d
16th term = 2 + 15*10
16th term = 2 + 150
16th term = 152.
☺ Hope it helps you ♥
By Rishi403
BeBrainly.
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