An ap has commondifference 2,sum of first n terms 49 and 7 term is 13 the value of n
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Answer:
Step-by-step explanation:
d=2
Sn= 49
a7=13
a+6d=13
a+6[2]=13
a+12=13
a=1
Sn = n/2[2a+[n-1]d]
49 = n/2[2*1+[n-1] 2]
98= n[2+2n-2]
98=n[2n]
98= 2n2
49=n2
n=7
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