An AP is 48,44,40. Find the nth term and the sum of the terms.
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Answer:
Here given a.p. is_
48,44,40.
where, a(First term)=48, d(Common difference)=44-48= -4
and n(number of terms)=3
Now,we have
nth term = a+(n-1)d= 48+(3-1)-4= 48-8=40.Ans
Now,sum of terms= n/2(a+nth term) =3/2(48+40)=3/2×88=3×44=132.Ans
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