Question

an AP, Sn=3n+5 then, the value of ‘d’ is:​

Answer 1

Answer:

For answer please see above assesment

Answer 2

Answer:

Solutions -

→ Sn = 3n + 5

So ,

n = 1

→ S1 = 3(1) +5 = 3+5 = 8

n=2

→ S2 = 3(2) +5 = 11

Let first term of given AP is a common difference is d .

So,

→ S1 = a1 = 8

→ S2 = a1 + a2

→ S2 = a1 ( a1 + d )

Then -

→ a1 + (a1 + d ) = 11

→ 8+8+d = 11

→ 16+d=11

→ d= 11-16