An ap starts from 50. if the ratio of 4th and 7th term is 28:31. find the common difference and S20
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Solution :
Given that, the first term of an AP is 50
Let us consider that the common difference is d
So, we get the AP as
50, 50 + d, 50 + 2d, ...
The 4th term be (50 + 3d) and the 7th term be (50 + 6d).
ATQ, (50 + 3d) : (50 + 6d) = 28 : 31
⇒ (50 + 3d) / (50 + 6d) = 28 / 31
⇒ 31 (50 + 3d) = 28 (50 + 6d)
⇒ 1550 + 93d = 1400 + 168d
⇒ 168d - 93d = 1550 - 1400
⇒ 75d = 150
⇒ d = 2
∴ the common difference is 2.
Now, S₂₀
= 20/2 * [ (2 * 50) + {(20 - 1) * 2} ]
= 10 * (100 + 38)
= 10 * 138
= 1380
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