An AP starts with a positive fraction and every alternate term is an integer. If the sum of the first 11 terms is 33, then the fourth term is [1]
Answers
fourth term = 2 if An AP starts with a positive fraction and every alternate term is an integer. If the sum of the first 11 terms is 33,
Step-by-step explanation:
sum of 11 terms = (11/2)(2a + 10d) = 33
=> 2a + 10d = 6
=> a + 5d = 3
d can be 1/2 , 3/2 , 5/2 as alternate number are integers
one possible solution a = 1/2 and d = 1/2
d = 3/2 will result in -ve a
there can be lot of other solutions if we take -ve values of d as well ( ignoring that case)
fourth term would be a + 3d
= 1/2 + 3/2
= 2
learn more:
n an ap if the 12th term is13 and sum of its first four terms is 24 find ...
https://brainly.in/question/8180136
If the sum of m terms of an AP is n and sum of n terms is m, then ...
https://brainly.in/question/7562249
Answer:
a4=2
Step-by-step explanation:
S11=33
11/2(2a+10d)=33
2a+10d=33×2/11
2a+10d=6 [FACTORIZE BY 2]
Then:
a+5d=3
ie, a6=3.
Therefore:
a4=2
[ since alternate terms are integers and given sum is possible]