Question

an apple falls form a height of 50 m and the weight of the apple is 50g find the speed

Answer 1

Solution:

Concept: Conservation of Energy.

At a height of 50m, the apple would have some amount of potential energy stored in it. When it is allowed to fall freely, it's potential energy gets converted to Kinetic Energy.

This process is called Transformation of energy which works on the principle of Conservation of Energy.

Potential Energy = mgh

Given, m = 50g, h = 50 m

→ Potential Energy = 0.05 Kg × 10 m/s² × 50 m

→ Potential Energy = 25 J

Kinetic Energy = 0.5 ( mv² )

→ Kinetic Energy = 25 J = 0.5 ( 0.05 × v² )

→ 25 = 0.025 v²

→ v² = 25/0.025 = 1000

→ v = √1000 = 10√10 m/s

Hence the speed of the ball while falling on the ground is 10√10 m/s.

Answer 2

Answer:

$\sqrt{1000} m/s$

Explanation:

The apple has a potential energy when it is at a height h and it gets converted to kinetic energy when it falls down

Potential energy the apple has =mgh

m=50g=0.05kg

g=10m/s^2

h=50m

Potential energy = 0.05×10×50=25J

The amount of kinetic energy also will be same

1/2×m(v)^2=25J

1/2×0.05(v)^2=25J

0.025V^2=25

V^2=1000

$v = \sqrt{1000}$