Question

an apple falls from a tree and strikes the ground in 0.5s . what is distance covered by the apple ? g = 10 ms-2.​

Answer 1

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▪An apple falls from a tree and strikes the ground in 0.5s . what is distance covered by the apple ? g = 10 ms-2.

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Given :-

Final Velocity = 0m/s

Time taken =0.5

Acceleration due to gravity =10 m/s square.

Solution:-

By using First law of motion

☞v =u +at

☞0m/s=u+10×0.5

☞u=5 m/s

Now,

By using Third Law of motion

$v {}^{2} - u {}^{2} = 2as \\ 0 {}^{2} - 5 {}^{2} = 2 \times 10 \times s \\ - 25 = 20 \times s \\ s = \frac{ - 25}{20} \\ s = - 1.25m$

Therefore the required answer will be 1.25m.

here negative sign show that the apple fall on earth

hope this answer helps you.

hope this answer helps you

Answer 2

It is given that an apple falls from a tree strikes the ground in 0.5 s. g = 10 m/s²

We have to find distance covered by apple.

Solution

As the apple falls freely, so initial velocity i.e. u = 0 m/s

Here, gravitational acceleration = 10 m/s²

Using 3rd equation of motion :

➺ s = ut + ½ gt²

Putting all values :

➺ s = 0 × 0.5 + ½ × 10 × (0.5)²

➺ s = 0 + 5 × 0.25

➺ s = 0 + 1.25

➺ s = 1.25 m

Hence, distance covered by apple = 1.25 m