Question

An apple is thrown with a speed of 30m/s in a direction 30 degrees above the horizon. Find out its horizontal range(g=9.8m/s^2)

A. 20m
B. 40m
C. 60m
D. 80m
E. 100m

Answer 1

Answer:

Option (D) 80 m

Explanation:

The path of the apple will describe a projectile motion

If the initial velocity is $u$, angle of projection $\theta$ then the horizontal range is given by

$R=\frac{u^2\sin2\theta}{g}$

Here given that

$u=30 m/s$

$\theta=30^\circ$

Therefore range is

$R=\frac{30^2\sin(2\times30^\circ)}{9.8}$

$\implies R=\frac{30\times 30\times \sin60^\circ)}{9.8}$

$\implies R=\frac{30\times 30\times(\sqrt{3}/2)}{9.8}$

$\implies R=\frac{15\times 30\times1.73)}{9.8}$

$\implies R=80\text{ m}$     (approx.)

Hope this helps.

Answer 2

Answer:

D:80m

Explanation: