An apple of mass 250 gram falls from a tree through a vertical distance of 6 m and reaches the ground with a velocity 8 m/s. If it experiences a constant air resistance during its fall, then the magnitude of work done by the air resistance on it is (g = 10 m/s2)
Answers
Answer:
7 joules haai
Explanation:
Work done = Change in K.E
Given : An apple of mass 250 gram falls from a tree through a vertical distance of 6 m and reaches the ground with a velocity 8 m/s.
it experiences a constant air resistance during its fall,
To Find : the magnitude of work done by the air resistance on it is (g = 10 m/s²)
Solution:
Change in potential Energy = mgΔh
m = 250 g = 1/4 kg
g = 10 m/s²
Δh = - 6 m
Decrease in potential energy = (1/4)(10)(6) = 15 joule
KE = (1/2)mv²
Increase in kinetic Energy = (1/2(1/4)(8)² - (1/2)(1/4)(0)²
= 8 Joule
Net Decrease in Energy = 15 - 8 = 7 joule
Hence the magnitude of work done by the air resistance on it = 7 joule
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