an appliance of resistance 22 ohm is connected across a'v' of 220 v. find the amount of charge flowing in 10 mins
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Resistance (R) = 22 Ω
Voltage (V) = 220 v
Current (I) = ?
So, as we know that V=IR:
implies, I = V/R = 220/22 = 10 A (ampere).
So, in 10 minutes,
Q = It
Q = 10 A×10 minutes
Q = 100 C (Coulomb).
Hence, the charge flow in 10 minutes is 100 C (Coulomb).
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i hope it will helps you friend
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