An application has 1,000 heavy users at a peak of 2 iops each and 2,000 typical users at a peak of 1 iops each, with a read/write ratio of 2:1. It is estimated that the application also experiences an overhead of 20 percent for other workloads. Calculate the iops requirement for raid 1, raid 3, raid 5, and raid 6.
Answers
1000 heavy users at peak of2 iops each=2000 iops and 2000 typical users at a peak of iops =2000 iops
20% overhead =4000*20/100=800
therefore total iops at peak workload =4800
read/write ratio 2:1 the 3200 read and write 1600
RAID 1 corrected iops (read+write pently=2)
=3200+(2*1600)=6400 iops
RAID 5 penlty 4 read write
3200+(4*1600)=9600 iops
RAID 6 pently read+write =6
3200+(6*1600)=12672 iops
hope it is helpful
The IOPS requirements are as follows.
The complete application produces 4000 x 1.20 = 4800 IOPS. This figure is inclusive of the overheads involved in it.
The ratio 2:1 means that nearly 33.3% are writes and 66.6% are reads.RAID 1/0 carries a write penalty of 2.
Hence, the disk load for writes and reads are 0.66 x 4800 + 2x (0.33 x 4800) = 6,336 IOPS.
RAID 5 carries a write penalty of 4. So, the complete disk load of writes and reads are 0.66 x 4800 + 4x (0.33 x 4800) = 9,504 IOPS.
The RAID 6 carries a write penalty of 6. Hence, the disk load of writes and reads are 0.66 x 4800 + 6x (0.33 x 4800) = 12,672 IOPS.