An applied force of 50 N is used to accelerate an object to the right across a frictional surface. The object encounters 10 N of friction. Use the diagram to determine the normal force, the net force, the mass, and the acceleration of the object. (Neglect air resistance.)
Answers
Answer:
To simplify calculations, an approximated value of g is often used - 10 m/s/s.
\tt\implies⟹ Answers obtained using this approximation are shown in parenthesis.
\tt\implies⟹ F_{norm}Fnorm = 80 N; m = 8.16 kg; F_{net}Fnet = 40 N, right; a = 4.9 m/s/s, right
\tt\implies⟹ ( F_{norm}Fnorm = 80 N; m = 8 kg; F_{net}Fnet = 40 N, right; a = 5 m/s/s, right )
\tt\implies⟹ Since there is no vertical acceleration, normal force = gravity force.
\tt\implies⟹ The mass can be found using the equation F_{grav}Fgrav = m • g.
\tt\implies⟹ The F_{net}Fnet is the vector sum of all the forces: 80 N, up plus 80 N, down equals 0 N. And 50 N, right plus 10 N, left = 40 N, right.
\tt\implies⟹ Finally, a = F_{net}Fnet / m = (40 N) / (8.16 kg) = 4.9 m/s/s.
ANSWER-
The mass can be found using the equation = m • g. The is the vector sum of all the forces: 80 N, up plus 80 N, down equals 0 N. And 50 N, right plus 10 N, left = 40 N, right. Finally, a = / m = (40 N) / (8.16 kg) = 4.9 m/s/s..