An aq. soln. of NaCl is malked 10%
w/w on
the bottle. The density of solution is 1.071 g/ml
calculate its molarity.
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2
Answer:
1.8M
Explanation:
Since it is given 10% w/w of NaCl so 10g of NaCl is present in 100g of solution
therefore, Mass of solution = 100g
density of solution = 1.071 g/ml
volume of solution = 100 / 1.071 = 93.3
no. of moles of solute = mass given ÷ molar mass = 10 ÷ 58.5
Molarity = no. of moles of solute ÷ vol. of solution
= (10/58.5) / 93.3 * 10^-3
= 10^4 / (58.5 * 93.3 * 10^ -3)
= 1.8 M
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