An aqua solution of oxalic acid dihydrate contains its 6.3 gram
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Explanation:
We know that the molar mass of oxalic acid is 90g. We also know that it is diprotic, having 2 H+ ions to donate in a reaction. Therefore, the Normality will be ½ the molarity. So, we need to add 5.625g of oxalic acid to water, and then add more water to make up 250ml of solution.
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Answer:
the volume of 0.1N NaOH required to completely neutralize 10ml of this solution is ? ... Oxalic acid is a dibasic acid as it can release two H+ Hence Molarity = (6.3 x 1000)/( 126 x 250) = 0.2
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