Math, asked by Urilima, 3 months ago

An aquarium is in the form of a cuboid whose external measures are 80cm × 30 cm × 40 cm . The bottom, side faces and back face are to be covered with a colour paper . Find the area of the Paper needed ?​

Answers

Answered by thebrainlykapil
226

\large\underline{ \underline{ \sf \maltese{ \: Question:- }}}

  • An aquarium is in the form of a cuboid whose external measures are 80cm × 30 cm × 40 cm . The bottom, side faces and back face are to be covered with a colour paper . Find the area of the Paper needed ?

 \\  \\

\large\underline{ \underline{ \sf \maltese{ \: Given:- }}}

  • Length of the Aquarium = \sf\green{ 80cm}
  • Height of the Aquarium = \sf\green{ 40cm}
  • Width of the Aquarium = \sf\green{ 30cm}

 \\  \\

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\large\underline{ \underline{ \sf \maltese{ \: Solution:- }}}

\begin{gathered}\begin{gathered}\begin{gathered}: \implies \underline\blue{ \boxed{\displaystyle \sf \bold\orange{\: Area \: of \: the \: Front \: Face   }} }\\ \\\end{gathered}\end{gathered}\end{gathered}

\qquad \quad {:} \longrightarrow \sf{\sf{80 \:  \times  \: 40 \:  {cm}^{2} }}\\ \\

\qquad\quad {:} \longrightarrow \underline \red{\boxed{\sf{Area \: of \: Front \: Face  \: = \: 3200 {cm}^{2}   }}}\\ \\

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\begin{gathered}\begin{gathered}\begin{gathered}: \implies \underline\blue{ \boxed{\displaystyle \sf \bold\orange{\: Area \: of \: the \: Top \: Face   }} }\\ \\\end{gathered}\end{gathered}\end{gathered}

\qquad \quad {:} \longrightarrow \sf{\sf{80 \:  \times  \: 30 \:  {cm}^{2} }}\\ \\

\qquad\quad {:} \longrightarrow \underline \red{\boxed{\sf{Area \: of \: Front \: Face  \: = \: 2400 {cm}^{2}   }}}\\ \\

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\begin{gathered}\begin{gathered}\begin{gathered}: \implies \underline\blue{ \boxed{\displaystyle \sf \bold\orange{\: T.S.A \: of \: Aquarium \: = \: 2( \: lb \:  +  \: bh \:  +  \: lh \: )  }} }\\ \\\end{gathered}\end{gathered}\end{gathered}

\qquad \quad {:} \longrightarrow \sf{\sf{ 2( \: 80 \times 30 \:  +  \: 30 \times 40 \:  +  \: 80 \times 40 \: )  }}\\ \\

\qquad \quad {:} \longrightarrow \sf{\sf{ 2( \: 2400\:  +  \: 1200 \:  +  \: 3200 \: )  }}\\ \\

\qquad \quad {:} \longrightarrow \sf{\sf{ 2\: \times \: 6800  }}\\ \\

\qquad\quad {:} \longrightarrow \underline \red{\boxed{\sf{ T.S.A \: of \: Aquarium \: = \:13600 {cm}^{2} }}}\\ \\

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Area of the colour paper required =

⠀⠀Total Surface Area - ( Area of front face+ Area of top face )

 \quad {:} \longrightarrow \sf{\sf{13600 \:  -  \: (3200 \:  +  \: 2400 \: ) \:  {cm}^{2}   }}\\ \\

 \quad {:} \longrightarrow \sf{\sf{13600 \:  - \: 5600 \:  {cm}^{2}   }}\\ \\

\qquad\quad {:} \longrightarrow \underline \red{\boxed{\sf{ Area \: of \: Paper  \: Req. = \:8000 {cm}^{2} }}}\\ \\

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\begin{gathered}\begin{gathered}\qquad \therefore\: \sf{ Area \: of \: Colour \: paper \: Req. \: = \underline {\underline{8000 {cm}^{2} }}}\\\end{gathered}\end{gathered}

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More For Knowledge :-

\underbrace\red{\boxed{ \sf \blue{ Formulas\: related\: to \:SA\: and \: \:  Volume : }}}

\begin{array}{|c|c|c|}\cline{1-3}\bf Shape&\bf Volume\ formula&\bf Surface\ area formula\\\cline{1-3}\sf Cube&\tt l^3}&\tt 6l^2\\\cline{1-3}\sf Cuboid&\tt lbh&\tt 2(lb+bh+lh)\\\cline{1-3}\sf Cylinder&\tt {\pi}r^2h&\tt 2\pi{r}(r+h)\\\cline{1-3}\sf Hollow\ cylinder&\tt \pi{h}(R^2-r^2)&\tt 2\pi{rh}+2\pi{Rh}+2\pi(R^2-r^2)\\\cline{1-3}\sf Cone&\tt 1/3\ \pi{r^2}h&\tt \pi{r}(r+s)\\\cline{1-3}\sf Sphere&\tt 4/3\ \pi{r}^3&\tt 4\pi{r}^2\\\cline{1-3}\sf Hemisphere&\tt 2/3\ \pi{r^3}&\tt 3\pi{r}^2\\\cline{1-3}\end{array}

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Answered by BetteRthenUhh
9

Step-by-step explanation:

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