Math, asked by vanshishSBS724, 11 months ago

An aquarium of fish ate 1.6 kg of fish food in June and twice that amount of fish food in July. In August the amount of food taken was 0.9 kg more than in July. What is the total mass of fish food eaten in the three months?

Answers

Answered by adnanasif1001
0

Answer:

8.9kg

Step-by-step explanation:

In June,Amount of food is 1.6 kg

So In July,Amount of food be 2x1.6=3.2kg

And In August, Amount of food be 3.2+0.9=4.1kg

Therefore The total mass of fish food eaten in three months is (1.6+3.2+4.1)kg=8.9kg

Required answer is 8.9kg

Answered by himanikamdi74
0

In June,Amount of food is 1.6 kg

So In July,Amount of food be 2x1.6=3.2kg

And In August, Amount of food be 3.2+0.9=4.1kg

Therefore The total mass of fish food eaten in three months is (1.6+3.2+4.1)kg=8.9kg

Required answer is 8.9kg

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