Question

an aquaus solution has molality 11.11 hence , mole fraction of solute in the solution is

Answer 1

An aqueous solution has morality equals to 11.11 that means 11.11 moles of solute are present in 1 kg or 1000 gm of solvent according to formula of molality.
As what is solvent no mentioned here we will consider water as solvent okk.
as 18 gm of water constitute 1 mole of water then 1000 gm of water will constitute 55.55 moles of water.
such Now we know no. of moles of both solute and solvent let's put these values in formula of molefraction
Molefraction = no. of moles of solute / (no. of moles of solute + no. of moles of solvent)

hence ,,molefraction = 11.11 /(11.11 +55.55 ) =11.11/ 66.66=0.167
I hope you got it well

Answer 2

Mole fraction of solute in the solution is calculated as 0.167

Explanation:

Given ,

An aqueous solution has molality equal to 11.11 which means 11.11 moles of solute are present in 1 kg or 1000 gm of solvent

According to the formula of molality.  

Here we will consider water as a solvent.  

As 18 gm of water constitute 1 mole of water

Then 1000 gm of water will constitute 55.55 moles of water.

Now we know no. of moles of bot,h solute and solvent  will be

Let us put these values in the formula of mole fraction

Mole fraction =number of moles of solute / (number of moles of solute + number of moles of solvent)

Therefore, mole fraction =$=\frac{11.11}{11.11+55.55}$  $= 0.167$

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