Question

an aqueous injection solution contains 5% dextrose by mass. find the molality​

Answer 1

Explanation:

Solution



Verified by Toppr

15% glucose C6H12O6 in H2O

15g of glucose in 85g of H2O

Solute⟶glucose⟶15g

Solvent⟶H2O⟶85g

No. of moles of solute=MolarMassGivenMass

Molar Mass of C6H12O6= 6x12+12x1+6x16

                                          = 72+12+96=180

n=18015=0.0833Density⟶1.5g/mL1.5g⟶1mL1g⟶1.51mL100g⟶1.51×100mL1.5100mLofsolution1.5100×

Answer 2

(dextrose = C6H12O6)

mass by % =5

5 grams of C6 H 12 O6  in 100 grams solution

moles of C 6 H12O6  = 5÷180

​                                 =0.027778

Volume = mass/ density  = 100/1.08

                                      =92.5925 g ml

Molarity = moles of C6H12O6 ÷  volume of solution

                                           =0.027778÷ 92.5925 gm

                                                     =0.3 M

Ans :- the molarity is 0.3M