Question

an aqueous solution boils at 100.512 degree Celsius. The freezing point of solution is Kf is 1.86 KKg per mol , Kb is 0.512 KKg per mol​

Answer 1

Answer:

Explanation:

−0.544∘C

−0.512∘C

−0.272∘C

−1.86∘C

Answer :

C

Solution :

0.15=0.512xm,m'=12(0.150.512)

ΔTf=1.86×0.150.512×12

Tf=−0.272∘C