Question

an aqueous solution consist of 460 ppm CH3CH2OH if the density of solution of 0.92g/cc then molarity of ch3ch2oh is​

Answer 1

Answer:

use the formula of ppm=mass of solute/mass of solution ×10^6.

Answer 2

The molarity of the solution is 0.92×10-²M.

Given:-

Mass of CH3CH2OH = 460ppm

Density of the solution = 0.92g/cc

To Find:-

The molarity of the solution.

Solution:-

We can simply find out the molarity of the solution by using these simple steps.

As

Mass of CH3CH2OH (m) = 460g

Density of the solution (d) = 0.92g/cc

Molar mass of CH3CH2OH = 46g

Mass of Solute = 10⁶g

Number of moles of CH3CH2OH = n

$n = \frac{460}{46}$

$n = 10$

Volume of solution = mass / density

$v = \frac{{10}^{6} }{0.92} ml$

Now, According to the formula of Molarity

$M = \frac{n \times 1000}{v}$

on putting the values,

$M = \frac{10 \times 1000}{ \frac{ {10}^{6} }{0.92} }$

$M = \frac{ {10}^{4} \times 0.92 }{ {10}^{6} }$

$M = 0.92 \times {10}^{ - 2}$

Hence, The molarity of the solution is 0.92×10-²M.

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