Chemistry, asked by Baymax19, 5 months ago

An aqueous solution containing 28% by weight of a liquid. A molecular
mas 140) has a vapour pressure of 0.210 bar at 37°C. Calculate the vapour
pressure of pure liquid (vapour pressure of water at 37°C = 0.198 bar​

Answers

Answered by Anonymous
3

Answer:

Manipur is the part of India that was most affected by the Second World War and its Burma Campaign. ... Bridle paths were turned into tarmac roads, additional jeep tracks were laid, airstrips built where none existed, and thousands of troops from other parts of India and the world began pouring in.

I hope this will be help you.

Answered by trupthi8
2

Answer:

An aqueous solution containing 28% by weight of a liquid,A(molecular mass is equal to 140)has a vapour pressure of 2.10 bar at 37 degree Celsius. calculate the vapour pressure of pure liquid( vapour pressure of water at 37 degree celsius is equal to 0.198 bar) it's answer is 0.458bar.

Similar questions