Question

An aqueous solution contains 28 % by mass koh. If density of the solution is 1.2 g/ml. Then calculate molality, molarity, % w/v and X.​

Answer 1

Explanation:

2.8% (m/v) solution of KOH means 2.8 g of solute in 100 ml of solution.

Weight of KOH =2.8 g

Volume of solution =100 ml

Molarity= Number of moles/Volume (l)

M=0.5M

Answer 2

Explanation:

Now mass of solvent in the solution= x−10020 x=10080x. ∴ Molality= (80x/100)x/200×1 000=6.25M.