Question

An aqueous solution freezes at -0.186. what is the elevation in boiling poibt

Answer 1

As the solution freezes at -0.186, Its Depression in Freezing point(ΔTf) is 0.186.

(Kf = 1.86 is called Cryoscopic constant)

→ ΔTf = Kf x m

→ 0.186 = 1.86 x m

→ m = 0.1

So, molality of the aqueous solution = 0.1

Elevation in boiling point,

(Kb =0.52 is called Ebullioscopic constant)

→ ΔTb = Kb x m

→ ΔTb = 0.52 x 0.1

→ ΔTb = 0.052

Thus the Elevation in Boiling point is 0.052

Hope it helps!!

Answer 2

Answer:

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