an aqueous solution freezes at 0.2°c . what is the molality of the solution. find also (1) elevation in boiling point (2)lower at vapour pressure at 25°c. given that kf= 1.86 k kg\mol, kb=0.512 k kg \mol and vapour pressure of water at 25°c is 23.756 mm of hg
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Answer:
(a)0−T
f
=iK
f
m
273−272.4=1.86×m or m=
1.86
.6
=.32m
(b) 100−T
b
=K
b
×m
100−K
b
×m=T
b
or T
b
=100−.16=99.84
(c) lowering of vapour pressure =
P
o
P
o
−P
=
760
760−22.756
=.97
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