an aqueous solution has 109.2g koh/l solution the solution density is 1.09 g/ml your task is to use 100.0 ml of this solution to prepare 0.250m
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0.25 m is answer so mark me as brainlist
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Molarity= GMW of KOHWeight of KOH×Vol(ml)1000
[GMW of KOH= Atomic weight of K+ atomic weight of O+ atomic weight of H=10+16+1=27]
⇒0.1=27Weight of KOH×1001000
Weight of KOH=102.7
Weight of KOH=0.27 g
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