Chemistry, asked by juhi9260, 8 months ago

an aqueous solution has urea and glucose in mass ratio 3 :1. if the mass ratio of water and glucose in solution is 10 :1, then the mole fraction of glucose in solutions.?​

Answers

Answered by AditiHegde
0

Given:

An aqueous solution has urea and glucose in mass ratio 3 :1.

The mass ratio of water and glucose in solution is 10 :1

To find:

The mole fraction of glucose in solutions.?​

Solution:

From given, we have,

The mass ratio of water and glucose in solution is 10:1

ng/nw = 1/10 .....(1)

and, n aqueous solution has urea and glucose in mass ratio 3:1.

mg/mu = 3/1 ......(2)

⇒ mu = x and mg = 3x

substituting the above values and molecular masses in equation (1), we get,

(3x/180) / (y/18) = 1/10 .....(3)

where the molecular mass of glucose = 180

the molecular mass of urea = 60

the molecular mass of water = 18

further solving the equation (3), we get,

3x = y

xg = moles of glucose / total moles

= (3x/180) / [(3x/180) + (x/60) + (y/18)]

= (x/60) / [(x/30) + (3x/18)]

= (1/60) / [(1/30) + (3/18)]

further solving the above equation, we get,

= 3/36

= 1/12

The mole fraction of glucose in solutions is 1/12.

Answered by Mora22
2

the mole fraction of glucose in solution is

1/110

Here is the solution •••

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