an aqueous solution has urea and glucose in mass ratio 3 :1. if the mass ratio of water and glucose in solution is 10 :1, then the mole fraction of glucose in solutions.?
Answers
Given:
An aqueous solution has urea and glucose in mass ratio 3 :1.
The mass ratio of water and glucose in solution is 10 :1
To find:
The mole fraction of glucose in solutions.?
Solution:
From given, we have,
The mass ratio of water and glucose in solution is 10:1
ng/nw = 1/10 .....(1)
and, n aqueous solution has urea and glucose in mass ratio 3:1.
mg/mu = 3/1 ......(2)
⇒ mu = x and mg = 3x
substituting the above values and molecular masses in equation (1), we get,
(3x/180) / (y/18) = 1/10 .....(3)
where the molecular mass of glucose = 180
the molecular mass of urea = 60
the molecular mass of water = 18
further solving the equation (3), we get,
3x = y
xg = moles of glucose / total moles
= (3x/180) / [(3x/180) + (x/60) + (y/18)]
= (x/60) / [(x/30) + (3x/18)]
= (1/60) / [(1/30) + (3/18)]
further solving the above equation, we get,
= 3/36
= 1/12
The mole fraction of glucose in solutions is 1/12.
the mole fraction of glucose in solution is
1/110
Here is the solution •••
