Question

an aqueous solution of 6.3g of oxalic acid dihydrate is made upto 250ml. the volume of 0.1N NaOH required to completely neutralize 10ml of this solution is ?

Answer 1

This question involves concept of volumetry

We can get the answer using the formula

N1V1=N2V2 ie. Principle of neutralization

Here

Oxalic acid is a dibasic acid as it can release two H+

Hence Molarity = (6.3 x 1000)/( 126 x 250) = 0.2

=> normality = 0.2 x 2 = 0.4

For req volume of NaOH

0.4 x 10 = 0.1 x V2

=> V2 = 40 ml

See : Molar concentration

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