Question

An aqueous solution of a compound with a molar mass of 34.02 g/mol is 24.0% by mass and has a density of 1.09 g/cm3
. What is the molarity of the solution?

Answer 1

Answer:

Which of the following do you except to be the least water soluble, and why? C10H8(s) , NH2OH(s) , C6H6(l) , CaCO3(s) .

Q13.1a

CaCO3 least soluble because it does not interact with H2O and the ion charge is significantly high.

Q13.1b

Which compound would be expected to readily dissolve in gasoline, and why?

CH3CH2OH(l), NH4 (aq), CH3(CH2)6COOH (s),BF3 (g)

Q13.1b

We would expect the caprylic acid ( CH3(CH2)6COOH )) to dissolve the easiest in gasoline because it is the only nonpolar molecule.

Q13.2a

What is the predicted solubility (either soluble or not soluble) in (1) water and (2) in benzene ( C6H6(l) )? Justify your answers.

Answer 2

The Molarity of the given solution is 7.69 M.

Given:  Density of an aqueous solution- 1.09g/cm³

            A compound with a molar mass of 34.02 g/mol is 24.0% by mass.

To find: Molarity of the solution

Solution:

In simplest terms, Molarity is the number of moles of a solute present in a specific volume of a solution. So, to find out the molarity of the solution, we need two values,

1. Volume of the solution

2. Number of moles of the solute.

For convenience, let us take a sample of 1 liter of this solution.

The volume of the solution is: 1 L

Since, 1 L = 1000 mL = 1000 cm³, we get,

1 mL = 1 cm³

Given, the density of the solution is 1.09 g/cm³. Density is defined as mass per unit volume.

Hence,

The density of the solution = Mass of the solution / Volume of the solution

Mass of the solution = Density x Volume

Mass of the solution = 1.09 g/cm³ x 1000 cm³

Mass of the solution = 1090 g

Since, we have the mass percent concentration of the given compound as present in the solution, which is 24 %. This means

24 g of the compound is present in 100 g of the solution.

Since the mass of our solution sample is 1090 g, the mass of the compound present in it is,

Mass of the compound dissolved, = 24/100 * 1090 = 261.6 g

Given, the molar mass of the compound is 34.02g/mol, we can calculate the number of moles of this compound present in the solution,

Number of moles, n, = Given mass/ Molar mass

The number of moles, n, = 261.6 g/ 34.02g = 7.69 moles

Now, as mentioned above, molarity is the number of moles of solute present in a certain volume of solution,

We have

1. Volume of the solution, V = 1 L

2. Number of moles of solute,n = 7.69

Molarity = n/V

Molarity =  7.69/1

Molarity of the solution = 7.69

To know more about molarity, check these links,

https://brainly.com/question/17138838#:~:text=Expert%2DVerified%20Answer&text=Molarity%20can%20be%20defined%20as,molecular%20weight%20of%20the%20compound.

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