Question

An aqueous solution of glucose is 5% by mass. The mole fraction of glucose in solution is

Answer 1

Answer:

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Answer 2

Mass 5%

=

$\frac{5}{100} g$

Now,

Glucose C6H12O6

(Molecular mass) = 72+ 12+ 96 = 180

Mole = g/Mo

$= \frac{5}{100 \times 180}$

$= \frac{ 1}{3600}$

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