Question

An aqueous solution of glycose is 20% in strength. the volume in which 1 g mole of it is dissolved will be

Answer 1

20% glucose solution means 20 g =20/180
moles are present in 100cc i.e., 0.1 L
Hence, 1 mole of glucose will present in
= (0.1x 182)/20 = 3.2 L