An aqueous solution of glycose is 20% in strength. the volume in which 1 g mole of it is dissolved will be
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20% glucose solution means 20 g =20/180
moles are present in 100cc i.e., 0.1 L
Hence, 1 mole of glucose will present in
= (0.1x 182)/20 = 3.2 L
moles are present in 100cc i.e., 0.1 L
Hence, 1 mole of glucose will present in
= (0.1x 182)/20 = 3.2 L
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