Chemistry, asked by archanaunni2003, 1 year ago

An aqueous solution of metal nitrate P reacts with sodium bromide solution to form yellow ppt of compound Q which is used in photography. Q on exposure to sunlight undergoes decomposition reaction to form metal present in P along with reddish brown gas. Identify P&Q . Write the chemical reaction & type of chemical reaction.

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Answers

Answered by maheshwaranlupp0yaxy
74
The metal nitrate P is silver nitrate.
It could be any metal nitrate but only silver chloride and silver bromide are used for photography.

AgNO3 + NaBr ------> AgBr + NaNO3.
This is double displacement reaction.

The yellow precipitate is AgBr.
AgBr is the compound Q.

AgBr in sunlight decomposes to form silver {the metal present in compound P (silver nitrate.).} and reddish brown gas bromine.

2AgBr ------> 2Ag + Br2.
This photochemical decomposition reaction as light energy is absorbed for the reaction to take place.


So,
compound P is AgNO3 (silver nitrate.).
Compound Q is AgBr (silver bromide.).

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- Maheshwaran.

archanaunni2003: very good answer!!
maheshwaranlupp0yaxy: Thank you
Answered by maimounapasha5463
5

Answer:

The metal nitrate P is silver nitrate.

It could be any metal nitrate but only silver chloride and silver bromide are used for photography.

AgNO3 + NaBr ------> AgBr + NaNO3.

This is double displacement reaction.

The yellow precipitate is AgBr.

AgBr is the compound Q.

AgBr in sunlight decomposes to form silver {the metal present in compound P (silver nitrate.).} and reddish brown gas bromine.

2AgBr ------> 2Ag + Br2.

This photochemical decomposition reaction as light energy is absorbed for the reaction to take place.

So,

compound P is AgNO3 (silver nitrate.).

Compound Q is AgBr (silver bromide.).

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