An aqueous solution of non volatile non electrolyte boils at 100.51 celsius.The freezing point of the solution is
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Answer:
We know that,
△T
b
=molality×K
b
0.17=molality×0.512
Molality of the solution =
0.512
0.17
m
Let depression in freezing point be △T
f
△T
f
=molality×K
f
=
0.512
0.17
×1.86=0.62
o
C
Thus, the freezing point of the solution
=0.00−0.62=−0.62
o
C
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