Chemistry, asked by robinkumar4344, 11 months ago

An aqueous solution of non volatile non electrolyte boils at 100.51 celsius.The freezing point of the solution is

Answers

Answered by farhaanaarif84
0

Answer:

We know that,

△T

b

=molality×K

b

0.17=molality×0.512

Molality of the solution =

0.512

0.17

m

Let depression in freezing point be △T

f

△T

f

=molality×K

f

=

0.512

0.17

×1.86=0.62

o

C

Thus, the freezing point of the solution

=0.00−0.62=−0.62

o

C

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