Question

An aracanut took 1 s to reach the ground from the tree. What will be the approximate height of the tree? (g= 10 m/s2) (20 m, 5 m, 12 m, 8 m)​

Answer 1

Answer:

ans.: 5m

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Answer 2

Answer:

The approximate height of the tree will be 5m.

Explanation:

The height of the tree, in this case, will be calculated using the motion's second equation which is as follows:

$s = ut + \frac{1}{2} at^{2}$

From the question we have given as follows;

u = 0 m/s ( as it had started from rest)

t = 1s  and a=g= 10m/$s^{2}$

Putting the above given in the equation we get,

$s = \frac{1}{2} at^{2}$

⇒$s = \frac{1}{2}$×10×1

⇒s = 5m

The approximate tree height is 5m from the ground. Therefore the answer is 5m.