An aracanut took 1 s to reach the ground from the tree. What will be the approximate height of the tree?
(g= 10 m/s2)
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Answer:
let us keep the height as displacement we get that
s= ut +1/2 (at²)
so we got t = 1 second
a = 10m per sec as only gravity is acting
u = 0
so substituting in
s = 0 + 1/2(10 × 1²)
s = half of ten the answer is 5
hope it helps mark as brainlyest
ans height is 5m
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