An archer pulls an arrow of weight 1.5 kg and the bow stores potential energy
equal to 100 J. If 73% of the energy is lost, then the speed (in m/s) at which the
arrow will travel is:
3
6
9
12
Answers
Answered by
1
Answer:
12
m travel to be a great day
Answered by
1
Given - Energy and mass
Find - Speed
Solution - The speed of the arrow will be 9.9 m/s.
The 73% of the given energy = 73/100*100
New energy = 73 Joules
Now, the potential energy stored in the bow will be converted to the kinetic energy of the arrow, which will cause it to travel.
So, 73 Joules will be equal to kinetic energy.
Kinetic energy = 1/2 * mass * velocity²
73*2/1.5 = velocity²
Velocity² = 146/1.5
Velocity² = 97.3
Velocity = ✓97.3
Velocity = 9.9 m/s.
Thus, the speed of the arrow will be 9.9 m/s.
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