An archery target has three regions formed by three concentric circles. If the diameters of the concentric circles are in the ratio1:2:3,then find the ratio of the areas of three regions.
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The diameter of three concentric circles are in the ratio of 1 : 2 : 3
Let the diameter of the three circles be 1 cm, 2 cm and 3 cm respectively.
So, their radii will also be in the ratio of 1 : 2 : 3.
Therefore, the radii of three concentric circle will be
1/2 cm , 2/2 cm = 1 cm and 3/2 cm
Ratio of their areas = πr₁² : πr₂² : πr₃²
= 22/7*1/2*1/2 : 22/7*1*1 : 22/7*3/2*3/2
= 1/4 : 1 : 9/4
So the ratio of their respective ratios is 1/4 : 1 : 9/4
Answer.
Hope This Helps :)
The diameter of three concentric circles are in the ratio of 1 : 2 : 3
Let the diameter of the three circles be 1 cm, 2 cm and 3 cm respectively.
So, their radii will also be in the ratio of 1 : 2 : 3.
Therefore, the radii of three concentric circle will be
1/2 cm , 2/2 cm = 1 cm and 3/2 cm
Ratio of their areas = πr₁² : πr₂² : πr₃²
= 22/7*1/2*1/2 : 22/7*1*1 : 22/7*3/2*3/2
= 1/4 : 1 : 9/4
So the ratio of their respective ratios is 1/4 : 1 : 9/4
Answer.
Hope This Helps :)
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