Question

An architect makes a model of a new house. The model shows a tile patio in the backyard. In the​ model, each tile has length 1/2 in
and width 1/6in
The actual tiles have length 3/4ft
and width 1/4ft
. What is the ratio of the length of a tile in the model to the length of an actual​ tile? What is the ratio of the area of a tile in the model to the area of an actual​ tile? Use pencil and paper. Describe two ways to find each ratio.

Answer 1

Answer:

Answer:

1/324

Step-by-step explanation:

Since, Here Each tile has length one third in and width one sixth in.

That is L_1 = 1/3 inches and W_1 = 1/6 inches

And, the actual tiles have length one half ft and width one fouth ft.

That is L_2 = 6 inches and W_2 = 3 inches ( because 1 foot = 12 inches)

Thus the ratio of length of the actual length of tile =

\frac{L_1}{L_2}= \frac{1/3}{6}= \frac{1}{18}

L

2

L

1

=

6

1/3

=

18

1

And, The ratio of tile in the model of the actual area = Area of the tile in model/ actual area

=\frac{1/3\times 1/6}{6\times 3}

6×3

1/3×1/6

= 1/324