Question

an area 5 × 10^-3 j m^2 is placed in an uniform electric field of (200i + 300j) N/C calculate the electric flux passing through this area​

Answer 1

Answer:

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Explanation:

Answer 2

Answer:

The electric flux passing through the area of 5 x 10⁻³ j m² is 1.5 Nm²/C .

Explanation:

Given that :

• Area of surface = 5 x 10⁻³ j m²
• Electric field, E = ( 200 i + 300 j ) N/C

To find :

• Electric flux through the surface

Solution :

• The electric flux through any surface is equal to the number of electric field lines passing through the surface normally.
• If E is the electric field and A is the surface area and θ is the angle between electric flux and normal of the surface. Then,
• Electric flux= E.A = |E| |A| cosθ
• E.A = (5 x 10⁻³ j).(200 i + 300 j) Nm²/C.
• Since, unit vector i and j are perpendicular to each other, their dot product is zero.
• E.A = 1500 x 10⁻³ Nm²/C = 1.5 Nm²/C.
• Hence, electric flux through the surface 5 x 10⁻³ j m² is 1.5 Nm²/C .