Question

An areo plane lands at 216 km/h and stops after covering a runway of 2km. Calculate the acceleration and the time, in which it comes to rest ​

Answer 1

Explanation:

Hope it is helpful to you

Answer 2

GIVEN:

• Inital velocity (u) = 216 km/h  = 216 x 5/18 = 60 m/s

• Final velocity(v) = 0 m/s

• Displacement after covering a runway of 2 km = 2000 m

TO FIND:

• Acceleration
• Time

SOLUTION:

Using the formula,

v^2 - u^2 = 2 x a x s

0 − 3600 = 2 a (2000)

Hence,  a = −0.9 m/s^2

v − u = a x t

0 − 60 = 0.9 t

t = 66.67 s

Therefore, Acceleration = -0.9 m/s^2 and Time = 66.67 s