Question

An areoplane takes off at an angle of 60° to the horizontal if the components of its
velocity along the horizontal is 250 km/hr what is the actual velocity ?​

Answer 1

❣️Hi❣️

Here is ur answer=>

Let the velocity of the plane be V m/s

horizontal component of velocity =

V cos 30°= 200

v x √3/2 = 200

v = 400/√3

=231 km/hr

vertical component of velocity is

V sin 30 = v/2=115.47 km/h

‼️I hope it will help u ‼️