Question

An areoplane when flying at a height of 3125m from the ground passes vertically below another plane at an instant when the angles of elevation of the two planes from the same point on the ground are 30degree &60degree respectively.find the distance between the two planes at instant.

Answer 1

from above process .....we get x=2083.33m

Answer 2

$<marquee>☺☺Hi there☺☺</marquee>$

let at the particular time aero plane be at the point B and at a distance of 3125 m from the vertical point C. i.e. BC=3125 m.

let another aero-plane be at the point A,  vertically above the first plane at an instant.

let D be the point of observation.

now in the right angled triangle BCD,

∠BDC=30 deg.

tan30°=BC/DC
1/√3= 3125/DC
=>DC=3125√3
now in the right angled triangle ACD
∠ADC=60°

tan 60°= AC/DC
√3 = AC/3125√3
AC=3125*3
AC=9375m

therefore the distance between the two planes at that instant is AB.

AC=AB-BC=9375-3125=6250m.

Thanks ♥♥