an arithmetic progression consist of 50terms of which third term is 12 and last term is 106 find the 29th term
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Answer:
Step-by-step explanation:
Total term are 50 so n=50
a3=12
a50=106
So,
a+2d=12
And
a+49d=106
So,
d=2
and hence a=8
So,a29=a+28d
8+28×2=a29
a29=64
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Answer:
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