Question

An arithmetic progression has first term 13. The nth term is 46 and the (3n)th term is 118. Find n.

Answer 1

Answer:

I solved it..incase any doubts .. Comment'on it ...or else if any method if you know please share .. or if it is wrong please correct it ....

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Answer 2

Answer:

the a1 =13 and an=46 a3 is 118 answer a+12d =46

Step-by-step explanation:

the a1 =13 and an=46 a3 is 118 answer a+12d =46 and a+2d=118 and is d=7.2 and an=a+(n-1)d so 46=13+(n-1)7.2

46-13=n-1×7.2

23=n-1×7.2

23÷7.2=n-1

3.19 =n-1

n=4(approx)

i hope it is help you