An Arithmetic progression has its first term a and common difference d. The sum of the first n terms of the progression is 10,000. Express a in terms of n and show that the nth term of the progression is 10,000/n+5(n-1).
Given that n term is less than 500, show that n^2-101n+2000 is less than 0 and hence, find the largest possible value of n
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Answer:500" (and any subsequent words) was ignored because we limit queries to 32 words.
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