An arithmetic sequence 6th term is 40and 10th term is 60.
a) what is the 13th term in this sequence
b) what is the total of first 25 terms
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Answer: 75 and 1875
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Step-by-step explanation:
t 6 = 40
i.e. a+5d =40
or, a= 40-5d------>1
and, t 10 = 60
or, a+9d = 60
or, 40 -5d +9d = 60
or, 4d = 20
d=5
and, a = 40 - 5* 5 = 15
Now, 1.
t 13 =a + 12d = 15 +12 *5 = 75
2.
S = n⁄2 {2a + (n − 1) d} where n= 25
= 25/2 { 2* 15 + 24 * 5}
= 12.5 * 150
=1875
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