Question

An arithmetic sequence has common difference equal to 10 and its 6th term is equal to 52. Find its 15th term.


Monday I have maths paper... please help me out with this question
my prelims are starting from Monday
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Answer 1

Answer:

d=10

t6=52

t15=?

$tn = a + (n - 1)d \\ t6 = a + (6 - 1)10$

$a + 5 \times 10 = 52$

$a + 50 = 52 \\ a = 2$

$t15 = 2 + (15 - 1)10 \\ = 2 + 14 \times 10$

$= 2 + 140 \\ = 142$

$t15 = 142$

that's is your answer

Answer 2

Answer:

142

Step-by-step explanation:

d= 10

tn=a+(n-1)d

52=a+(6-1)10

52=a+5(10)

52=a+50

a=52-50

a=2

15 th term = 2+(15-1)10

15 th term=2+14×10

15 th term=2+140

15 th term=142