Question

An Arithmetic series first tag 12, the Fifteenth is 110.
How much the difference and the Thirty tag

A1= 12
A15= 110
a30 = ?
d= ?​​

Answer 1

Answer:

Given series is 6,12,18...

In a arithmetic series a

n

=a+(n−1)d, where a is the first term of the sequence, d is the common difference and n is the number of the term to find.

Since the first term is 6 and second term is 12, therefore, the common difference is :

d=12−6=6 implies d=6

Now we find a

30

given that a=6, d=6 and n=30

a

30

=6+(30−1)(6)=6+174=180